Comments on: Học SQL cơ bản cho Data Analyst trong 10p – Phần 0

By: Vi Nam

Vi Nam — Thu, 18 May 2023 09:16:38 +0000

In reply to An Pham. +) Ở bài 2 dù dùng group by name hay ko dùng thì đều ra kết quả giống nhau mà nhỉ +) Hàm SUM(cột A) sẽ cộng tất cả các giá trị của cột A lại (tức là nó sẽ cộng theo chiều dọc). Nên SUM(attack+defense+speed) sẽ cộng tất cả các giá trị từ 3 cột attack, cột defense, cột speed lại với nhau (cộng cả chiều ngang với chiều dọc) nên Tong_chiso sẽ bị cao lên khá nhiều

By: Alan Huỳnh

Alan Huỳnh — Sun, 03 Jul 2022 03:18:58 +0000

1.select type1, count(type1) as num_pokemon
from pokemon p
group by type1

2.select type1
from pokemon p
where attack<50 and defense<50 and speed<50
group by type1
limit 10

3.select type1, avg(attack) ,avg(defense)
from pokemon p
group by type1

4.select name
from pokemon p
where is_legendary = 1 and type1 = 'fire' and type2 is not null

5.select type1, min(base_total), avg(base_total) ,max(base_total)
from pokemon p
group by type1

6.select type1, max(base_total) as highest_base_total
from pokemon p
where not is_legendary
group by type1
order by highest_base_total desc
limit 10

Em xin phép nộp bài ạ, cảm ơn anh

By: Thành Trung

Thành Trung — Tue, 24 Aug 2021 14:42:38 +0000

1. select type1 as pokemon_type ,count(*) as quantity
from pokemon
group by type1

2. select name as pokemon_name ,attack+defense+speed as properties_sum
from pokemon
order by properties_sum asc
limit 10

3. select type1 as pokemon_type ,AVG(attack) as avg_A ,AVG(defense) as avg_D
from pokemon
group by pokemon_type

4.select *
from pokemon
where is_legendary = 1 and type1 type2 and type1=’fire’

5. select type1 as pokemon_type ,max(base_total) as highest_base_total ,min(base_total) as lowest_base_total ,avg(base_total) as avg_base_total
from pokemon
group by type1

6. select *
from pokemon
where is_legendary=0
order by base_total desc
limit 10

Cám ơn anh rất nhiều <3

By: Thành Trung

Thành Trung — Mon, 23 Aug 2021 14:26:03 +0000

Anh cho em hỏi trong quá trình làm, nếu đang làm dở dang và muốn lưu lại để lúc rảnh tiếp tục làm mà không bị mất các câu lệnh đã nhập thì làm cách nào ạ

By: vi nguyen

vi nguyen — Mon, 14 Dec 2020 01:32:02 +0000

1.
select type1, count(type1)
from pokemon p
group by type1
2.
select name, attack , defense, speed
from pokemon p
order by (attack+defense+speed) asc
limit 10

By: An Pham

An Pham — Sat, 12 Sep 2020 11:53:37 +0000

In reply to Trung Do Thanh. bro cho mình hỏi, ở bài 2 tại sao lại phải group by name nhỉ? mình có thử ko group by name, thì bị lặp kết quả. ngoài ra, hình như phần SUM(attack+defense+speed) là chưa đúng, nếu dùng SUM mình thấy phần Tong_chiso bị cao lên khá nhiều, ko biết là do đâu nữa

By: HIEU

HIEU — Sat, 04 Jul 2020 07:14:39 +0000

4, select *
from pokemon p
where is_legendary = 1 and type1 = “fire” and type2 is not null
5, select type1 as name, max(base_total) as caonhat, min(base_total) as thapnhat, avg(base_total ) as trungbinh
from pokemon p
group by type1
6, select name, base_total
from pokemon
where is_legendary = 0
group by name
order by base_total desc
limit 10
Ps: This is aff of SQL having a result from me, in case it wrong i want to get any comment and opinion from friends.

By: HIEU

HIEU — Sat, 04 Jul 2020 06:16:27 +0000

1, select type1 as name, count(type1) as soluong
from pokemon p2
group by type1
2, select type1 as name, attack, defense, speed
from pokemon
group by type1
order by (attack + defense + speed) asc
limit 10
3, select type1 as name, attack, defense, (attack+defense)/2 as trungbinh
from pokemon
group by type1
the results from newbie

By: Trung Do Thanh

Trung Do Thanh — Thu, 11 Jun 2020 07:06:48 +0000

1/ SELECT type1, COUNT(type1) as Qty FROM pokemon
GROUP by type1
ORDER by Qty DESC

2/SELECT name,attack,defense,speed, SUM(attack+defense+speed) as Tong_chiso
FROM pokemon
GROUP BY name
ORDER BY Tong_chiso ASC
LIMIT 10

3/SELECT type1,attack,defense, AVG(attack+defense) as Trungbinh_Chiso FROM pokemon
GROUP BY type1
ORDER BY Trungbinh_chiso DESC

4/SELECT name,type1, type2, is_legendary FROM pokemon
WHERE type1 = ‘fire’ AND is_legendary = 1 AND type1 type2
GROUP BY name

5/SELECT type1, MAX(base_total) as max_total, MIN(base_total) AS min_total, AVG(base_total) AS avg_total
FROM pokemon
GROUP BY type1
ORDER BY max_total DESC

6/SELECT name, base_total FROM pokemon
WHERE is_legendary = 0
GROUP BY name
ORDER by base_total DESC
LIMIT 10

By: Lê Đức Trọng

Lê Đức Trọng — Tue, 25 Feb 2020 11:27:25 +0000

Em gửi phần của mình. Cảm ơn anh nhiều ạ.
1.
select type1, count(name) as num_pokemon
from pokemon p
group by type1
order by num_pokemon desc
2.
select name, (attack+defense+speed) as chiso
from pokemon p
group by chiso
order by chiso asc
limit 10
3. Cho biết điểm trung bình Attack và Defense của mỗi loại Pokemon. Sử dụng Type1.
select type1, avg (attack+defense) as trungbinh
from pokemon p
group by type1
order by trungbinh asc
4.
select name, type1, type2, is_legendary
from pokemon p
where is_legendary=1 and type1=’Fire’ and type1 and type2
5.
select type1, max(base_total) as lonnhat, avg(base_total) as trungbinh, min(base_total) as nhonhat
from pokemon p
group by type1
6.
select name, (base_total) as chiso
from pokemon p
where not is_legendary
group by name
order by base_total desc
limit 10